2/(x^2-4x)-7/x=5/(x-4)

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Solution for 2/(x^2-4x)-7/x=5/(x-4) equation: 


D( x )

x = 0

x-4 = 0

x^2-(4*x) = 0

x = 0

x = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x^2-(4*x) = 0

x^2-(4*x) = 0

x^2-4*x = 0

x^2-4*x = 0

DELTA = (-4)^2-(0*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+4)/(1*2) or x = (4-16^(1/2))/(1*2)

x = 4 or x = 0

x in (-oo:0) U (0:4) U (4:+oo)

2/(x^2-(4*x))-(7/x) = 5/(x-4) // - 5/(x-4)

2/(x^2-(4*x))-(5/(x-4))-(7/x) = 0

2/(x^2-4*x)-5*(x-4)^-1-7*x^-1 = 0

2/(x^2-4*x)-5/(x-4)-7/x = 0

x^2-4*x = 0

x^2-4*x = 0

x*(x-4) = 0

x-4 = 0 // + 4

x = 4

x*(x-4) = 0

2/(x*(x-4))-5/(x-4)-7/x = 0

2/(x*(x-4))+(-5*x)/(x*(x-4))+(-7*(x-4))/(x*(x-4)) = 0

2-7*(x-4)-5*x = 0

2-5*x-7*x+28 = 0

30-12*x = 0

(30-12*x)/(x*(x-4)) = 0

(30-12*x)/(x*(x-4)) = 0 // * x*(x-4)

30-12*x = 0

30-12*x = 0 // - 30

-12*x = -30 // : -12

x = -30/(-12)

x = 5/2

x = 5/2

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